x^2+120x-625=0

Solution for x^2+120x-625=0 equation:

x^2+120x-625=0

a = 1; b = 120; c = -625;
Δ = b2-4ac
Δ = 1202-4·1·(-625)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-130}{2*1}=\frac{-250}{2}
=-125
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+130}{2*1}=\frac{10}{2}
=5
$